Basic Don’t Come Strategy: Temporary Odds Hedge Explained
Don’t Pass · Don’t Come · Temporary lay Odds · Hedge audit
The Basic Don’t Come method combines a Don’t Pass contract with a new Don’t Come bet and temporarily lays enough Odds to make a next-roll 7 profitable. It is a short hedge-management rule, not insurance against every result and not a player advantage.
Corrected opening example
With a $5 Don’t Pass on point 6, lay $6 Odds to win $5, then place $5 in Don’t Come. If the next roll is 7, Don’t Come loses $5 while Don’t Pass wins $5 and the lay Odds wins $5: net +$5.
The original used $5 as lay Odds behind a $5 Don’t Pass on 6. True Odds against 6 pay 5 to 6, so a clean single-Odds example lays $6 to win $5. A house may accept other amounts and round; ask the dealer to state “lay X to win Y.”
Next-roll outcomes before Don’t Come travels
| Next roll | Don’t Come | Existing DP on 6 | Immediate effect |
|---|---|---|---|
| 7 | Loses $5 | Wins $5 flat + $5 Odds | Net +$5 |
| 2 or 3 | Wins $5 | Remains | +$5; DP unresolved |
| 11 | Loses $5 | Remains | −$5; DP unresolved |
| 12, bar 12 | Pushes | Remains | No change |
| 4/5/6/8/9/10 | Travels to that number | May resolve if 6 | Two contracts may remain |
What happens after Don’t Come travels
If 10 rolls, the $5 Don’t Come travels behind 10. The method then removes the temporary Odds from Don’t Pass, leaving a $5 Don’t Pass against 6 and $5 Don’t Come against 10. A later 7 wins both flat bets. A 6 loses the Don’t Pass while the 10 contract remains; a 10 loses Don’t Come while the 6 contract remains.
If 6 rolls while it is the table point, the Don’t Pass and its Odds lose immediately. The new Don’t Come also travels behind 6, but the point being made ends that table game; its contract continues into the next come-out. This is why “insured” is too broad a description.
What the hedge changes
- The temporary lay Odds makes the immediate 7 net positive instead of roughly breaking even.
- True Odds adds no house edge, but the $6 can still be lost if point 6 repeats.
- Removing Odds after the DC travels reduces future dollar exposure.
- The two flat contracts retain their normal house edges.
- No recent roll makes 7 more likely.
This contributor method was originally credited to Larry Edell. Its opening lay amount depends on the established point; the same dollar stake cannot win the same Odds profit on every number. Review Don’t Come, Don’t Pass, and lay Odds.
Use a three-line state card
Before the next roll, record three lines: the table point, each contract number, and every dollar currently at risk. In the opening example those lines read “point 6,” “$5 Don’t Pass plus $5 Don’t Come,” and “$6 temporary Odds; $16 total exposed.”
After a box number sends the Don’t Come wager behind that number, cross out the temporary Odds only when they are actually returned to the rack. Then rewrite the two contract numbers and the remaining exposure. This prevents a removed hedge, a traveling contract, or a new come-out from being counted as though the previous layout still existed.
Scale the lay amount to the desired profit
To repeat the opening example with $30 Don’t Pass and a new $30 Don’t Come, choose temporary Odds to win $30: lay $60 against 4/10, $45 against 5/9, or $36 against 6/8. An immediate 7 then gives $30 flat profit plus $30 Odds profit minus the $30 DC loss, for a $30 net gain. The total exposed amounts are $120, $105 and $96 respectively.
At point 6, a repeat of 6 instead loses the $30 Don’t Pass and $36 Odds: $66 is gone, while the new $30 DC travels behind 6. It does not repay that loss simply by traveling. On the next come-out it still wins on 7 and loses on 6. Check the house’s allowed Odds limit before requesting these amounts, and keep returned stake separate from winning profit.

Can someone explain something about this to me? If your don’t pass was $30 instead of $5 and you wanted to bring a don’t come bet through safely, wouldn’t you have to put more than $30 behind the don’t pass because of the odds for that number? is it because of the smaller amount($5) or can you actually place $30 behind to win $30 straight up?
So,if the don’t pass was$30 instead of $5 as above and you wanted to bring a $30 don’t come bet through safely,wouldn’t you have to make it more than $30? Can you just increase the original bet by $30 and have it pay even money? That’s the way it sounds to me, you lay $5 (or in my example, $30) on the odds and it would pay $30 plus your $30 don’t pass?
I don’t think that’s right. the don’t pass/odds wouldn’t win $10.
It is just a reprint from another site…. I should probably just delete it 🙂 In the meantime, you can check out the Crapspit preferred strategy!
If the point is 6/8, you lay $6 to win $5
If the point is 5/9, you lay $9 to win $6
If the point is 4/10, you lay $10 to win $5