$20 Horn Bet Payout: What You Win When 12 Rolls

Sam Originally published Updated

Horn payout · $20 example · 12 rolls

On a standard $20 Horn bet, $5 is placed on each of 2, 3, 11, and 12. If 12 rolls and the table pays 30 to 1, the winning $5 component earns $150 while the other three $5 components lose. Net profit: $135. Total chips returned: $155.

The answer in one table

The answer in one table: Total Horn wager.
Total Horn wager$20
Amount on 12$5
Profit on 12 at 30 to 1$150
Loss on 2, 3, and 11−$15
Net profit$135
Total returned including the winning $5 stake$155

Why three parts lose

The Horn is not one wager with one payout. It is four simultaneous one-roll bets:

Why three parts lose: Horn number; Share of a $20 Horn; Standard payout; Result when 12 rolls.
Horn numberShare of a $20 HornStandard payoutResult when 12 rolls
2$530 to 1Loses $5
3$515 to 1Loses $5
11$515 to 1Loses $5
12$530 to 1Wins $150 profit; $5 stake returned

That is why subtracting the full $20 from $150 is wrong: the $150 figure is already profit on the winning $5 component. Only the other $15 loses. $150 minus $15 equals $135 net profit.

Profit versus total return

Casino payoffs are easy to misread because 30 to 1 describes profit, while 31 for 1 describes the total returned including the winning stake. On the $5 bet on 12:

  • 30 to 1: $5 × 30 = $150 profit, plus the $5 stake;
  • 31 for 1: $5 × 31 = $155 total return.

Both expressions describe the same standard payoff. Check the layout because some tables use different proposition paytables.

What if 3 or 11 rolls?

A $5 component on 3 or 11 wins $75 profit at 15 to 1. The other three $5 bets lose $15, producing $60 net profit and $80 total chips returned.

What if 3 or 11 rolls?: Winning Horn result; Net profit on $20 Horn; Total returned.
Winning Horn resultNet profit on $20 HornTotal returned
2 or 12 at 30 to 1$135$155
3 or 11 at 15 to 1$60$80
Any other total−$20$0

Why the standard Horn edge is 12.5%

There are six winning combinations: one way each to roll 2 and 12, plus two ways each to roll 3 and 11. Thirty of the 36 combinations lose all four units. On a four-unit Horn:

[(2 × 27) + (4 × 12) − (30 × 4)] ÷ 36 = −0.5 unit

The expected loss is 0.5 unit on 4 units wagered, or 12.5%. A recent run of Horn numbers does not improve the next roll’s probability.

Use multiples of four. A standard Horn divides equally among four numbers. A non-multiple requires a Horn High instruction or a house-specific split.

See the full Horn and Whirl guide for Horn High, Whirl, payout variations, and house edges.

Reviewed by Sam: This reader-question page keeps the useful $20 example while separating profit from total return and removing the old claim that a visible trend justifies the wager.

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