Craps bet guide · Reviewed September 4, 2026
C&E combines two one-roll wagers: one part on Any Craps (2, 3, or 12) and one part on Eleven. Under the standard 7-to-1 Any Craps and 15-to-1 Eleven paytable, a $1 C&E produces $3 net profit when craps rolls and $7 net profit when 11 rolls. The combined house edge is 11.11%.
Sam’s verdict
C&E is simpler and slightly less expensive than a four-number Horn bet, but it is still a high-edge one-roll proposition. Its real value as a lesson is understanding component bets, net payouts, and how one winning half must pay for the losing half.
What C and E mean
- C: Any Craps—2, 3, or 12—commonly pays 7 to 1.
- E: Eleven—11—commonly pays 15 to 1.
C&E covers the same four totals as a Horn, but the structure is different. Horn contains four individual number bets. C&E groups 2, 3, and 12 into one Any Craps component and keeps 11 as the second component.
The paired C/E circles on some layouts also help the crew identify player position. One chip straddling the two areas is conceptually split between C and E, but the casino’s accepted minimums and chip-handling procedure control how that is actually booked.
The $1 C&E calculation
| Roll | Winning half | Losing half | Net profit |
|---|---|---|---|
| 2, 3, or 12 | $0.50 × 7 = $3.50 | −$0.50 Eleven | $3 |
| 11 | $0.50 × 15 = $7.50 | −$0.50 Any Craps | $7 |
| Any other total | $0 | Both halves lose | −$1 |
The arithmetic explains the familiar $3/$7 net result. It does not mean every casino literally accepts two 50-cent proposition wagers. Fractional execution, minimums, and whether an odd-dollar chip can straddle the two components are house procedures.
If you want clean whole-dollar components, a $2 C&E is conceptually $1 Any Craps plus $1 Eleven.
Larger C&E examples
A $5 C&E is conceptually $2.50 on each component:
- If 2, 3, or 12 rolls, the C half earns $17.50 and the losing E half costs $2.50, leaving $15 net.
- If 11 rolls, the E half earns $37.50 and the losing C half costs $2.50, leaving $35 net.
A $10 C&E divides cleanly into $5 components. Craps nets $30; Eleven nets $70. The wager scales linearly, so a larger amount increases dollars at risk but does not improve the percentage edge.
C&E versus Horn
| Call | Underlying pieces | Main difference |
|---|---|---|
| $1 C&E | Conceptually $0.50 Any Craps + $0.50 Eleven | 11.11% combined edge; fractional execution may be house-dependent |
| $2 C&E | $1 Any Craps + $1 Eleven | Whole-dollar components |
| $4 Horn | $1 each on 2, 3, 11, 12 | Four individual number bets; standard combined edge 12.50% |
The important distinction is not the nickname—it is what wagers are actually underneath the chips. See the Horn and World guide and the Any Craps guide before treating the calls as interchangeable.
Why the house edge is 11.11%
Across 36 equally likely dice combinations:
- Any Craps wins on 4 combinations and contributes 4 × $3 = $12 in net profit to the $1 C&E.
- Eleven wins on 2 combinations and contributes 2 × $7 = $14.
- The other 30 combinations lose the full $1, or −$30.
Net expectation is $12 + $14 − $30 = −$4 per $36 wagered, which is −11.11%.
That is why changing the amount, pressing after a win, or repeating the wager does not change the underlying percentage cost.
Position and settlement
On layouts with paired C/E circles, the chip’s position helps identify the player who owns it. If a payoff appears to be assigned to the wrong position, do not move the center chip yourself. Identify your rail position and ask the crew to verify the bet.
The winning component is paid while the losing component is deducted. That is why experienced crews often announce the net payoff rather than narrating the two halves separately.
How to make a C&E bet
- Wait until proposition bets are open.
- State the amount and “C and E” clearly.
- Put or deliver the chips where the stickperson directs.
- Confirm the amount if the casino’s minimums make the split unclear.
- After a win, say whether you want the wager repeated or down.
What about the winning 50-cent bet itself? If the craps part of the C&E pays 7:1, wouldn’t you be entitled to $3.50 in winnings less the losing eleven bet plus the original $.50 craps bet? That would make $3.50 (rounded down to $3.00).
Bill, thanks for your post. Your question basically answers itself. Let’s break it down. With a $1 C&E bet where $0.50 is on the Any Craps and $0.50 is on the 11, an Any Craps winner pays $3.50 at 7:1 (therefore, the first part of your question is true; yes, you are entitled to $3.50 in winnings). With an Any Craps win, the 11 part of the C&E bet loses, so you lose $0.50 (therefore, the second part of your question is true; yes, you lose the 11). The third part of your question is also true, “…plus the original $0.50 craps bet” (i.e., the original $1 chip remains on the table as a new C&E bet, unless you tell the dealer to take it down). The $0.50 loss for the 11 is accounted for in the net payout to you. So, you get your net payout (i.e., $3.00) and the original $1 chip remains on the table as a new C&E bet for the next roll (i.e., that original $1 chip now comprises the $0.50 you get to keep for the original $0.50 Any Craps bet that you won, and a new $0.50 bet on the 11). Remember, the $0.50 loss for the 11 is taken out of your net payout, so that’s how the original $1 chip remains on the table for a new C&E bet on the next roll, unless you tell the dealer to take it down. Let’s look at it another way. Suppose the casino actually has $0.50 chips, so you toss the dealer two chips (i.e., total $1) and tell him you want to bet the C&E. The dealer puts one $0.50 chip on the “C” and the other $0.50 chip on the “E.” The shooter rolls a 12. The dealer takes down the $0.50 chip for your losing Eleven (the casino now owns that chip). Then, the dealer pays you $3.50 for your winning Any Craps and he leaves your original $0.50 chip on the table as a new Any Craps bet (you currently own that chip). (NOTE: It’s common practice for most casinos to leave the winner on the table as a new bet unless you specifically tell him to take it down.) Although the dealer usually leaves the winning chip on the table as a new bet, let’s suppose for this example that he takes it down and gives it back to you with your winning payout. So, the net amount in your hand is $4.00 (i.e., $3.50 for your winning payout + plus your original $0.50 chip for your winning Any Craps = $4.00). Now, let’s look at the net when the dealer leaves your original $1 chip on the table. The dealer pays you $3.00 (not $3.50 as in the example above) because he subtracts the $0.50 portion of the losing Eleven. Your original $1 chip stays on the table as a new C&E bet (you currently own that $1 chip). So, the $3.00 payout + $1 on the table = $4.00. In both examples, your net amount is $4.00. I suspect that your confusion is simply because of the fact that, typically, the dealer subtracts the losing 11 from the payout and then leaves the original $1 chip on the table as a new C&E bet. Yes, this game can get confusing, but if you break it down as I did above, then everything begins to make sense. Good luck and have fun at the tables!
Thanks. I was thinking of it as picking the original bet up as well. If I’m going to leave the dollar on the table, you are right.
You bet a dollar on the C & E. I thought the payout on C is 3 x 2, if you want the E bet to be left on? I thought the payout on E is the 7 x 2, if you want the C bet to be left on. What am I missing from your payout answer? Where are you getting 7:1 and 15:1?
Chgodon, thanks for your question. It sounds like you have the same question as another of our guests. Rather than repeating the same answer, we refer you to the question that our guest, Bogus_Bill, sent to us. It’s located below on this article about the C&E bet. In our response to Bogus_Bill, we go into great detail to explain the payout. Make sure you click the “see more” link to reveal our entire response. Let us know if that doesn’t answer your question. Thanks for visiting the Crapspit, and good luck at the tables!