$22 Inside Regression: Rules, Payouts, and Probability
$22 Inside · Remove two winners · Rebuild · $2–$4 lock-in
The $22 Inside regression starts with minimum Place bets on 5, 6, 8, and 9. The first two different numbers that hit are collected and removed; later hits rebuild those positions. Its strength is simple exposure reduction, not a promise that two hits will arrive before 7.
Two removed winners can lock $2 to $4
Every starting inside bet wins $7. Removing the winning stake returns another $5 or $6. After two different numbers hit, the rack contains $24 to $26 against the original $22, while two smaller positions remain working.
Starting layout and first-hit return
| Number | Place bet | Win | Win plus removed stake |
|---|---|---|---|
| 5 or 9 | $5 | $7 | $12 returned to rack |
| 6 or 8 | $6 | $7 | $13 returned to rack |
Step-by-step method
- Wait for a point if you do not want the Place bets working on the come-out.
- Place $5 each on 5 and 9 and $6 each on 6 and 8: $22 total.
- When the first number hits, collect $7 and remove that winning bet.
- When a different active number hits, collect $7 and remove it.
- Leave the other two inside bets working, or call them off according to the written exit rule.
- On each later active-number hit, use $5 or $6 of the $7 payout to restore one removed number. Do not press.
- After both positions are rebuilt, either repeat the reduction cycle or collect until 7.
Result after the first two different hits
| Removed winners | Cash returned | Still working | If 7 is next |
|---|---|---|---|
| 5 and 9 | $24 | $12 on 6/8 | +$2 cycle |
| One $5 number and one $6 number | $25 | $11 | +$3 cycle |
| 6 and 8 | $26 | $10 on 5/9 | +$4 cycle |
Those profits are locked only if the returned chips stay in the rack. Rebuilding puts part of the cash back at risk.
Follow one rebuild without double-counting stakes
Start with $5 on 5 and 9 and $6 on 6 and 8. If 5 pays first, collect its $7 profit and remove its $5 stake: $12 in the rack. If 6 pays next, collect $7 and remove $6: the rack reaches $25, while $6 on 8 and $5 on 9 remain working. A 7 now loses those $11 of Place bets, leaving a $3 gain against the original $22 layout.
If 8 hits instead, its $6 Place bet stays up and pays $7. Use $5 of that payout to restore Place 5 and rack $2; the rack is now $27 with $16 working. If 9 then hits, use $6 of its $7 profit to restore Place 6 and rack $1: $28 in the rack with all $22 back on the layout. A following working 7 loses that $22 layout, so the four-hit path finishes $6 ahead. Restoring a removed stake is a new exposure decision; the $5 and $6 cannot be counted as both racked and working.
Probability of reaching the reduction
At the start, 5, 6, 8, and 9 have 18 combinations and 7 has six. Ignoring neutral totals, the first inside hit arrives before 7 with probability 18/24, or 75%. After removing the winner, the remaining active combinations depend on which number hit. Combining those paths gives approximately a 51.84% chance of removing two different winners before 7.
That is close to a coin flip, not a near-certainty. A seven-out before any hit loses $22; one hit followed by 7 still leaves a loss of $9 or $10.
Practical rules
- A repeat of a number already removed is not a collection unless you restored it.
- State whether the point number is included.
- Confirm correct $5 and $6 units at the table minimum.
- Keep the optional line bet outside this system’s accounting.
- Do not increase the next $22 entry because the prior hand failed.
Compare the larger $132 Inside regression and review the underlying Place-bet payouts.
